在Java中将多个字符串分组为通用字符串

Question

我必须将多个字符串组合成一个来进行比较.这个分组应该完全像Java OO范例:一个"描述"子字符串的字符串.例:

String one = "hammer";
String two = "screwdriver";
String three = "pliers";

现在让我们说你要"描述"它们:

String str = "tool"

上面的所有字符串都是工具 现在,我的代码有一个,两个,三个字符串,并将它们更改为"工具".因此,例如,字符串1成为工具,字符串2和字符串3相同.如何"分类"他们？另一个扩展示例:

String one = "hammer"
String two = "screwdriver";
String three = "pliers";
String four = "horse";
String five = "cat";
String six = "dog";

public void stringConverter(String str)
{
    if ("string match to an animal")
        str = "animal";
    if ("string match to a tool")
        str = "tool";
}

也许这是一个愚蠢的事情,但现在我没有任何想法!谢谢!

编辑:我的团队是有限的,我知道我只有猫,狗,马,锤等...编辑2:很难表达我!它应该是这样的:

Group Animal = {cat, dog, horse}
Group Tools = {hammer, screwdriver}

// methods to recognize to wich one of the two groups is categorizable

Map是一个好主意,但必须在每个运行时填充.是不是有一些静态的东西,比如把它们直接写成大括号？它应该像枚举,但以前从未使用过!

Answer 1

我会开始这样的事情.

public class Category
{
    private final String name;
    private final Set<String> items;

    public Category(String name)
    {
        this.name = name;
        this.items = new HashSet<String>();
    }

    public String getName()
    {
        return name;
    }

    public void add(String... items)
    {
        for (String item : items)
        {
            this.items.add(item);
        }
    }

    public boolean contains(String item)
    {
        return this.items.contains(item);
    }
}

然后,

Category tools = new Category("tool");
tools.add("hammer", "screwdriver", "pliers");

Category animals = new Category("animal");
animals.add("horse", "dog", "cat");

最后,

// Guava for brevity
List<Category> categories = Lists.newArrayList(tools, animals);

public void stringConverter(String str)
{
    for (Category c : categories)
    {
        if (c.contains(str)) return c.getName();
    }

    return "not found";
}