Objective-C中的时间戳

Question

我有约会,例如:2012-02-07 14:09:46.109950我需要时间戳,因为1328623786.568740有我的代码:

NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyy-MM-dd HH:mm:ss.SSSSSS"];
[dateFormat setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
NSDate *date = [dateFormat dateFromString:@"2012-02-07 14:09:46.109950"];
NSTimeInterval interval = [date timeIntervalSince1970];
[dateFormat release];

NSLog(@"%f", interval);

但现在,我有这样的结果1328623786.110000,.110000 - 是圆的.请帮助我得到不圆润的结果.

Answer 1

功能 CFAbsoluteTimeGetCurrent();

要么 CFDateGetTimeIntervalSinceDate(CFDateRef theDate, CFDateRef otherDate);

要么 CFDateGetAbsoluteTime(CFDateRef theDate);

更新:您的值在这里自动舍入 NSDate *date = [dateFormat dateFromString:@"2012-02-07 14:09:46.109950"];

NSLog(@"%@", [dateFormat stringFromDate:date]);

结果:

2012-02-07 14:09:46.110000