如何在同一个appdelegate.swift中使用google +和facebook登录

Question

我的应用程序使用谷歌+登录和我的appdelegate.swift我有:

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
    // Override point for customization after application launch.

    var configureError: NSError?
    GGLContext.sharedInstance().configureWithError(&configureError)
    assert(configureError == nil, "Error configuring Google services: \(configureError)")

    GIDSignIn.sharedInstance().delegate = self

    return true

}


func application(application: UIApplication,
    openURL url: NSURL, sourceApplication: String?, annotation: AnyObject) -> Bool {
        return GIDSignIn.sharedInstance().handleURL(url,
            sourceApplication: sourceApplication,
            annotation: annotation)
}

现在我想插入facebook登录,但我必须在appdelegate.swift中添加此代码:

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
    // Override point for customization after application launch.
    return FBSDKApplicationDelegate.sharedInstance().application(application, didFinishLaunchingWithOptions: launchOptions)
}

func application(application: UIApplication,
    openURL url: NSURL,
    sourceApplication: String?,
    annotation: AnyObject?) -> Bool {
        return FBSDKApplicationDelegate.sharedInstance().application(
            application,
            openURL: url,
            sourceApplication: sourceApplication,
            annotation: annotation)
}

但是这个返回错误因为函数"应用程序"已经存在,我怎样才能同时执行google +和facebook appdelegate.swift谢谢.

Answer 1

您的应用程序应该处理Facebook and谷歌链接,然后返回,true如果or其他人可以处理给定的链接.

func application(application: UIApplication, openURL url: NSURL, sourceApplication: String?, annotation: AnyObject) -> Bool {

        let googleDidHandle = GIDSignIn.sharedInstance().handleURL(url,
            sourceApplication: sourceApplication,
            annotation: annotation)

        let facebookDidHandle = FBSDKApplicationDelegate.sharedInstance().application(
            application,
            openURL: url,
            sourceApplication: sourceApplication,
            annotation: annotation)

        return googleDidHandle || facebookDidHandle
}

并在didFinishLaunching:

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
    // Override point for customization after application launch.

    var configureError: NSError?
    GGLContext.sharedInstance().configureWithError(&configureError)
    assert(configureError == nil, "Error configuring Google services: \(configureError)")

    GIDSignIn.sharedInstance().delegate = self

    return FBSDKApplicationDelegate.sharedInstance().application(application, didFinishLaunchingWithOptions: launchOptions)

}

Answer 2

在Swift 3中,需要这样做:

覆盖并实现下一个方法:

   func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any]) -> Bool {
    let sourceApplication =  options[UIApplicationOpenURLOptionsKey.sourceApplication] as? String
    let annotation = options[UIApplicationOpenURLOptionsKey.annotation]

    let googleHandler = GIDSignIn.sharedInstance().handle(
        url,
        sourceApplication: sourceApplication,
        annotation: annotation )

    let facebookHandler = FBSDKApplicationDelegate.sharedInstance().application (
        app,
        open: url,
        sourceApplication: sourceApplication,
        annotation: annotation )

    return googleHandler || facebookHandler
}

然后:

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    PFFacebookUtils.initializeFacebook(applicationLaunchOptions: launchOptions)
    FBSDKApplicationDelegate.sharedInstance().application(application, didFinishLaunchingWithOptions: launchOptions)

    var configureError: NSError?
    GGLContext.sharedInstance().configureWithError(&configureError)
    assert(configureError == nil, "Error configuring Google services: \(String(describing: configureError))")

    return true
}