Iva*_*nov 1 sql oracle join subquery ora-00918
两个Subselects运行良好独立.
但我希望加入他们,他们总是给出"ORA-00918:列模糊定义".我不明白为什么?
两个子选项都使用其他名称.
SELECT *
FROM (SELECT aods.user_id,
aods.firstname,
aods.lastname,
Aods.DEPARTMENT,
cods.jc_name
FROM personas aods
LEFT JOIN
user_jc cods
ON aods.user_id = cods.user_id
WHERE cods.jc_name LIKE '%ADM%') ods
FULL OUTER JOIN
(SELECT abl.user_id,
abl.firstname,
abl.lastname,
Abl.DEPARTMENT,
bbl.ug_name
FROM personas abl
LEFT JOIN
ru_ug bbl
ON abl.user_id = bbl.user_id
WHERE Bbl.UG_NAME LIKE '%ADM%'
AND bbl.rss_name = 'TIR') bl
ON ods.user_id = bl.user_id
Run Code Online (Sandbox Code Playgroud)
因为你select *在顶部做了一个.
user_id
firstname
lastname
DEPARTMENT
Run Code Online (Sandbox Code Playgroud)
存在于两个子查询中,并且select *它将获得两个具有相同名称的列.
如果要合并两个子查询(这样生成的列集合user_id, firstname, lastname, DEPARTMENT, jc_name, ug_name),您应该进行自然连接:
SELECT *
FROM (SELECT aods.user_id, aods.firstname, aods.lastname, aods.department,
cods.jc_name
FROM personas aods LEFT JOIN user_jc cods
ON aods.user_id = cods.user_id
WHERE cods.jc_name LIKE '%ADM%') ods
NATURAL JOIN
(SELECT abl.user_id, abl.firstname, abl.lastname, abl.department,
bbl.ug_name
FROM personas abl LEFT JOIN ru_ug bbl ON abl.user_id = bbl.user_id
WHERE bbl.ug_name LIKE '%ADM%' AND bbl.rss_name = 'TIR') bl
Run Code Online (Sandbox Code Playgroud)
相反,如果您想要所有不同的列,则应明确列出它们:
SELECT ods.user_id, ods.firstname, ods.lastname, ods.department, ods.jc_name,
bl.user_id, bl.firstname, bl.lastname, bl.department, bl.ug_name
FROM (SELECT aods.user_id, aods.firstname, aods.lastname, aods.department,
cods.jc_name
FROM personas aods LEFT JOIN user_jc cods
ON aods.user_id = cods.user_id
WHERE cods.jc_name LIKE '%ADM%') ods
FULL OUTER JOIN
(SELECT abl.user_id, abl.firstname, abl.lastname, abl.department,
bbl.ug_name
FROM personas abl LEFT JOIN ru_ug bbl ON abl.user_id = bbl.user_id
WHERE bbl.ug_name LIKE '%ADM%' AND bbl.rss_name = 'TIR') bl
ON ods.user_id = bl.user_id
Run Code Online (Sandbox Code Playgroud)
在您的评论中,您说您希望nvl()在每个列上使用外部联接.对我来说它工作正常:
SELECT NVL (ods.user_id, bl.user_id), NVL (ods.firstname, bl.firstname),
NVL (ods.lastname, bl.lastname), NVL (ods.department, bl.department),
ods.jc_name, bl.ug_name
FROM (SELECT '1' user_id, 'ods2' firstname, NULL lastname,
'ods3' department, 'ods4' jc_name
FROM DUAL) ods
FULL OUTER JOIN
(SELECT '1' user_id, NULL firstname, 'bl2' lastname, 'bl3' department,
'bl4' ug_name
FROM DUAL) bl ON ods.user_id = bl.user_id
Run Code Online (Sandbox Code Playgroud)
你在做一些额外的东西order by吗?