如何从元素中获取html(),排除另一个元素?

Ale*_*x G 5 jquery

对不起真正的愚蠢问题.但它无论如何都无效.

<html>
<head>
<script src='js/jquery.js' type='text/javascript'></script>
<script type='text/javascript'>
  $(document).ready(function() {
    var htmlcontent = $('.content').not('.dontgrab').html();
    alert(htmlcontent); // returns EVERYTHING
  });
</script>
</head>
<body>
<div class='content'>
  BEFORE
  <div class='dontgrab'>DON'T GRAB</div>
  AFTER
</div>
</body>
</html>
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试过$(".content*:not('.dontgrab')").html(); //返回NULL

请帮忙.

谢谢.

Ric*_*ton 12

这应该这样做:

var clone = $('div.content').clone();
clone.find('.dontgrab').remove();

var html = clone.html();
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