C++如何使find_if不仅返回应用pred的第一个对象为true

Question

这意味着允许用户输入他/她希望搜索的姓名,联系人和地址.我想要做的是显示所有应用pred的对象是真的,但我似乎无法让它工作.

static string searchName, searchContact, searchAddress;

bool search_User(User &u)
{ 
   return (u.getName() == searchName && u.getContact() == searchContact && u.getAddress() == searchAddress);

}
void searchUser(vector<User> &u)
{
    cout << "Name of user: ";
    getline(cin, searchName);
    cout << "Contact of tutor: ";
    getline(cin, searchContact);
    cout << "Adress of user: ";
    getline(cin, searchAddress);
    vector<User>::iterator i;
    i = find_if(u.begin(), u.end(), search_User);
    cout << i->getName() << i->getContact() << i->getAddress() << endl;
}

Answer 1

通常的解决方案是使用std::copy_if:

std::vector<User> matches;
std::copy_if(v.begin(), v.end(), std::back_inserter(matches),
    [Name, Contact, Address](User const& u)
    { return u.getName() == Name && u.getContact() == Contact && u.getAddress() == Address;});

或者只写一个经典的循环

for (User& u : users) {
  if (search_User(u) {
    std::cout << u; // Assumes you've implemented operator<<(ostream&, User)
  }
} 

Answer 2

伪代码:

for(iterator i = v.begin(); 
    (i = find_if(i, v.end(), ...)) != v.end(); ++i )
{
    print *i;
}