12 java linux networking ip-address
如何通过Java获取Linux上的计算机的IP?
我在网上搜索了一些例子,我发现了一些关于NetworkInterface类的内容,但我无法理解我是如何得到IP地址的.
如果我在同一时间运行多个网络接口会发生什么?将返回哪个IP地址.
我真的很感激一些代码示例.
PS:我到目前为止使用的是InetAddress类,这对于跨平台应用程序来说是一个糟糕的解决方案.(WIN/Linux的).
adr*_*rau 30
不要忘记外部不可见的环回地址.这是一个提取第一个非环回IP(IPv4或IPv6)的函数
private static InetAddress getFirstNonLoopbackAddress(boolean preferIpv4, boolean preferIPv6) throws SocketException {
Enumeration en = NetworkInterface.getNetworkInterfaces();
while (en.hasMoreElements()) {
NetworkInterface i = (NetworkInterface) en.nextElement();
for (Enumeration en2 = i.getInetAddresses(); en2.hasMoreElements();) {
InetAddress addr = (InetAddress) en2.nextElement();
if (!addr.isLoopbackAddress()) {
if (addr instanceof Inet4Address) {
if (preferIPv6) {
continue;
}
return addr;
}
if (addr instanceof Inet6Address) {
if (preferIpv4) {
continue;
}
return addr;
}
}
}
}
return null;
}
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gre*_*awk 13
为什么InetAddress不是一个好的解决方案?我没有在关于跨平台兼容性的文档中看到任何内容?
此代码将枚举所有网络接口并检索其信息.
import java.io.*;
import java.net.*;
import java.util.*;
import static java.lang.System.out;
public class ListNets
{
public static void main(String args[]) throws SocketException {
Enumeration<NetworkInterface> nets = NetworkInterface.getNetworkInterfaces();
for (NetworkInterface netint : Collections.list(nets))
displayInterfaceInformation(netint);
}
static void displayInterfaceInformation(NetworkInterface netint) throws SocketException {
out.printf("Display name: %s\n", netint.getDisplayName());
out.printf("Name: %s\n", netint.getName());
Enumeration<InetAddress> inetAddresses = netint.getInetAddresses();
for (InetAddress inetAddress : Collections.list(inetAddresses)) {
out.printf("InetAddress: %s\n", inetAddress);
}
out.printf("\n");
}
}
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以下是示例程序的示例输出:
Display name: bge0
Name: bge0
InetAddress: /fe80:0:0:0:203:baff:fef2:e99d%2
InetAddress: /121.153.225.59
Display name: lo0
Name: lo0
InetAddress: /0:0:0:0:0:0:0:1%1
InetAddress: /127.0.0.1
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小智 5
这段代码工作4me:
import java.net.InetAddress;
import java.net.NetworkInterface;
import java.net.SocketException;
import java.util.Enumeration;
public class ShowIp {
public static void main(String[] args) throws SocketException {
NetworkInterface ni = NetworkInterface.getByName("eth0");
Enumeration<InetAddress> inetAddresses = ni.getInetAddresses();
while(inetAddresses.hasMoreElements()) {
InetAddress ia = inetAddresses.nextElement();
if(!ia.isLinkLocalAddress()) {
System.out.println("IP: " + ia.getHostAddress());
}
}
}
}
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