什么是在RichTextBox中排序行的最佳方法

Question

我正在寻找排序RichTextBox行的最佳方法,我现在正在使用它:

public void SortLines(object sender, EventArgs e)
{
    TextPointer pStart = TextInput.Document.ContentStart;
    TextPointer pEnd = TextInput.Document.ContentEnd;
    TextRange text = new TextRange(pStart, pEnd);

    string[] lines = text.Text.Split('\n');
    Array.Sort(lines);
    text.Text = String.Join(String.Empty, lines);
}

1. 有最佳方​​法吗？

2. 当我调用它时,光标放在第一个RichTextBox行中,我该如何将它放在以前的位置？我尝试设置pStart/pEnd和CaretPositiom,但属性是只读的.

我希望这很清楚.提前致谢.

Answer 1

就排序而言，此解决方案与您建议的解决方案没有什么不同，但我发现它更优雅+它处理光标位置和选择：

public void SortLines(object sender, EventArgs e)
{
       rtb.HideSelection = false; //for showing selection
        /*Saving current selection*/
        string selectedText = rtb.SelectedText;
        /*Saving curr line*/
        int firstCharInLineIndex = rtb.GetFirstCharIndexOfCurrentLine();
        int currLineIndex = rtb.Text.Substring(0, firstCharInLineIndex).Count(c => c == '\n');
        string currLine = rtb.Lines[currLineIndex];
        int offset = rtb.SelectionStart -firstCharInLineIndex;


        /*Sorting*/
        string[] lines = rtb.Lines;
        Array.Sort(lines, delegate(string str1, string str2) { return str1.CompareTo(str2); });
        rtb.Lines = lines;

        if (!String.IsNullOrEmpty((selectedText)))
        {
            /*restoring selection*/
            int newIndex = rtb.Text.IndexOf(selectedText);
            rtb.Select(newIndex, selectedText.Length);
        }
        else
        {   /*Restoring the cursor*/

            //location of the current line
            int lineIdx = Array.IndexOf(rtb.Lines, currLine);
            int textIndex = rtb.Text.IndexOf(currLine);
            int fullIndex = textIndex + offset;
            rtb.SelectionStart =  fullIndex;
            rtb.SelectionLength = 0;
        }
}