枚举数组 - 转换为NSArray

Question

有

enum {MyA, MyB, Null};
typedef NSNumber myEnum;

要么

typedef enum {MyA, MyB, Null} myEnum;

1)如何创建数组

myEnum* myEnumTemp[] = {MyA, MyB};

只是给 "Implicit conversion of 'int' to NSNumber* is disallowed with ARC(ref. counting)

2)如果你能够创建一个数组如何将其转换为NSArray？

Answer 1

尝试这样做:

typedef enum { MyA, MyB, Null } myEnum;

然后,要创建数组,请将数字包装到NSNumbers对象中:

NSArray *a = [NSArray arrayWithObjects:[NSNumber numberWithInteger:MyA],
                                       [NSNumber numberWithInteger:MyB],
                                       nil];

Answer 2

在Obj C:

enumArray = @[@(enum1),@(enum2)];

在Swift中:

enumArray = NSArray(objects: enum1.rawValue, enum2.rawValue);

Answer 3

基本上,您需要将值包装在NSNumber对象中.

#define INT_OBJ(x) [NSNumber numberWithInt:x]

[array addObject:INT_OBJ(MyA)];

你的其他数组没有任何问题,你应该像这样定义它:

typedef enum {MyA, MyB, Null} myEnum;

myEnum values[] = { MyA, MyB };

问题是您将myEnum定义为a NSNumber,它不等于枚举值(int).