gho*_*der 3 android android-intent
这是我第一次活动中的代码:
Intent i = new Intent(this, OtherScreen.class);
i.putExtra("id1", "first");
i.putExtra("id2", "second");
startActivity(i);
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第一个,第二个是我想要传递的值.在我的另一堂课上我有这个:
Intent i = getIntent();
Bundle extras = i.getExtras();
String result = extras.getString("id1");
System.out.println("yeah"+result);
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但是在我运行之后,我的结果是空的.你能帮助我吗?如果我以这种方式编写我的getString,我会收到语法错误.
String result = extras.getString(id1); //id1 cannot be resolved to a variable
String result = extras.getString("id1","default value"); // remove argument
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Intent i = new Intent(yourcurrentactivity.this, OtherScreen.class);
i.putExtra("id1", "first");
i.putExtra("id2", "second");
startActivity(i);
Bundle extras = getIntent().getExtras();
if (extras != null) {
String result = extras.getString("id1");
System.out.println("yeah"+result);
}
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