如何从命令变量在bash中创建数组？

Question

我试图让SNMP走进一个数组,变量中的数据是格式"data1 data2" "data3 data4".基本上我只想要双引号之间的数据,无论可能有多少空格.

我已经google了大约一个半小时,无法弄清楚如何正确格式化数组.

这是我现在拥有的代码的嗤之以鼻......

IN=$(snmpwalk -Oqv -v2c -c$community $ipaddr .1.3.6.1.4.1.32050.2.1.26.2)
portdesc=($(echo $IN))

这确实把它放在一个数组中,但是当我试图访问第一个数据集"data1而不是"data1 data2".我可以作弊,只使用两个变量,但我宁愿以正确的方式做,只是引用我想要的项目的数组.如果你可以帮助我,我将永远伟大.

echo "DEBUG0: ${portdesc[@]}"
echo "DEBUG1: ${portdesc[0]}"

DEBUG0: "Relay Output" "Expansion Power" "Expansion Tripped" "Switch Input" "Radio 1 Power" "Radio 2 Power" "Radio 3 Power" "Radio 4 Power" "Radio 1 Sync" "Radio 2 Sync" "Radio 3 Sync" "Radio 4 Sync" "Radio 1 Tripped" "Radio 2 Tripped" "Radio 3 Tripped" "Radio 4 Tripped" "SyncPipe Power" "SyncPipe Tripped" "Switch to NMEA" "2D Fix" "3D Fix" "DGPS Fix" "1PPS Active" "Radio 1 Power" "Radio 2 Power" "Radio 3 Power" "Radio 4 Power" "Radio 1 Sync" "Radio 2 Sync" "Radio 3 Sync" "Radio 4 Sync" "Radio 1 Tripped" "Radio 2 Tripped" "Radio 3 Tripped" "Radio 4 Tripped" "SyncPipe Power" "SyncPipe Tripped" "Switch to NMEA" "2D Fix" "3D Fix" "DGPS Fix" "1PPS Active" "Radio 1 Power" "Radio 2 Power" "Radio 3 Power" "Radio 4 Power" "Radio 1 Sync" "Radio 2 Sync" "Radio 3 Sync" "Radio 4 Sync" "Radio 1 Tripped" "Radio 2 Tripped" "Radio 3 Tripped" "Radio 4 Tripped" "SyncPipe Power" "SyncPipe Tripped" "Switch to NMEA" "2D Fix" "3D Fix" "DGPS Fix" "1PPS Active"

DEBUG1: "Relay

来自CLI的SNMP命令

$ snmpwalk -O qv -v2c -c<community> <ip> .1.3.6.1.4.1.32050.2.1.26.2
"Relay Output"
"Expansion Power"
"Expansion Tripped"
"Switch Input"
"Radio 1 Power"
"Radio 2 Power"
"Radio 3 Power"
"Radio 4 Power"
"Radio 1 Sync"
"Radio 2 Sync"
"Radio 3 Sync"
"Radio 4 Sync"
"Radio 1 Tripped"
"Radio 2 Tripped"

Answer 1

如果您提供示例输入(我不知道snmpwalk的输出是什么样的),我会对此更有信心.但据我所知,你期望数组只在换行符处分割文本,而不是在空格处.默认情况下,bash在空格,制表符和换行符处拆分.要改变这种行为,你可以修改的值IFS(我 NPUT ˚F ield 小号 eparator):

OLDIFS="$IFS"
IFS=$'\n'      # newlines are the only separator
IN=($(my_command ...))
IFS="$OLDIFS"

额外的两行保存并恢复IFS的值,以防脚本的其他部分依赖它.

(顺便说一句,如果你谷歌"bash数组换行",你会发现一些解释这个的东西.)