Python捕获任何异常,并使用变量值打印或记录回溯

Question

当我用sys.excepthook捕获意外错误时

import sys
import traceback

def handleException(excType, excValue, trace):
    print 'error'
    traceback.print_exception(excType, excValue, trace)

sys.excepthook = handleException

h = 1
k = 0

print h/k

这是我得到的输出

error
Traceback (most recent call last):
   File "test.py", line 13, in <module>
      print h/k
ZeroDivisionError: integer division or modulo by zero

如何在traceback simillar中包含变量值(h,k,...)到http://www.doughellmann.com/PyMOTW/cgitb/？当我包含cgitb结果是一样的.

编辑:

很好的答案我只是这样修改它所以它在文件中记录跟踪

def handleException(excType, excValue, trace):
    cgitb.Hook(logdir=os.path.dirname(__file__),
      display=False,
      format='text')(excType, excValue, trace)

Answer 1

通过查看源代码cgitb.py,您应该可以使用以下内容:

import sys
import traceback
import cgitb

def handleException(excType, excValue, trace):
    print 'error'
    cgitb.Hook(format="text")(excType, excValue, trace)

sys.excepthook = handleException

h = 1
k = 0

print h/k