流利的Nhibernate映射通过两个非主键列联接

Question

我想知道是否有一种方法可以在不创建视图的情况下将具有两个非主键列的两个表联接在一起？我有一个名为“ Make”的表，其中包含“ Name”和“ Year”列，我想与另一个名为“ Style”的表，其中包含“ MakeName”和“ MakeYear”列。一个“制作”可以有多个“样式”。这是我到目前为止创建的实体：

public class Make
{
    public virtual int Id { get; set; }
    public virtual string Name { get; set; }
    public virtual string Year { get; set; }
    public virtual IList<Style> Styles { get; set; } 
}

public class Style
{
    public virtual int Id { get; set; }
    public virtual string MakeName { get; set; }
    public virtual string MakeYear { get; set; }
    public virtual string Class { get; set; }
    public virtual Make Make { get; set; }
}

这些也是我到目前为止的类映射：

public class MakeMap : ClassMap<Make>
{
    public MakeMap()
    {
        Id(x => x.Id);
        Map(x => x.Name);
        Map(x => x.Year);
        // Bad mapping...
        //HasManyToMany(x => x.Styles).Table("Make").AsBag()
          .ParentKeyColumn("MakeName")
          .ChildKeyColumn("MakeYear").Cascade.All();
        Table("Make");
    }
}

public class StyleMap : ClassMap<Style>
{
    public StyleMap()
    {
        Id(x => x.Id);
        Map(x => x.Class);
        Map(x => x.MakeName);
        Map(x => x.MakeYear);
        // Ends up overwriting the "MakeName" column
        References(x => x.Make).Column("MakeName").PropertyRef("Name").
              Column("MakeYear").PropertyRef("Year");
        Table("Style");
    }
}

谢谢！

Answer 1

我更喜欢第一个的3个选择

1. 选项：

   更改样式，以在样式表中db schema包括品牌id而不是名称和年份

2. 选项

References(x => x.Make)
    .Formula("(Select s.Id FROM Style s WHERE s.Name = MakeName AND s.Year = MakeYear)");

3. 选项

public class Make
{
    public virtual int Id { get; set; }

    public virtual MakeId BusinessId { get; private set; }
}

public class MakeId
{
    public virtual string Name { get; set; }
    public virtual string Year { get; set; }
}

public class MakeMap : ClassMap<Make>
{
    public MakeMap()
    {
        Id(x => x.Id);
        Component("BusinessId", c => 
            c.Map(x => x.Name);
            c.Map(x => x.Year);
        });

        HasMany(x => x.Styles)
          .PropertyRef("BusinessId")
          .KeyColumns.Add("MakeName", "MakeYear")
          .Cascade.All();
        Table("Make");
    }
}

public class StyleMap : ClassMap<Style>
{
    public StyleMap()
    {
        Table("Style");

        Id(x => x.Id);
        Map(x => x.Class);

        References(x => x.Make)
            .PropertyRef("BusinessId")
            .Columns.Add("MakeName", "MakeYear");
    }
}