ome*_*ach 0 c++ arrays typedef visual-c++
typedef std::map<std::string,int> string2intMap;
typedef string2intMap arrOfMaps[3] ;
//map : string --> array of maps of <std::string,int>
std::map<std::string,arrOfMaps> tryingStuff;
//map : string --> int
string2intMap s;
s["key"]= 100;
tryingStuff["hello"][0] = s;
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上面的代码没有编译,有问题的行是:tryingStuff ["hello"] [0] = s;
这是编译器大喊:
c:\program files (x86)\microsoft visual studio 10.0\vc\include\map(215): error C2440: '<function-style-cast>' : cannot convert from 'int' to 'std::map<_Kty,_Ty> [3]'
2> with
2> [
2> _Kty=std::string,
2> _Ty=int
2> ]
2> There are no conversions to array types, although there are conversions to references or pointers to arrays
2> c:\program files (x86)\microsoft visual studio 10.0\vc\include\map(210) : while compiling class template member function 'std::map<_Kty,_Ty> (&std::map<_Kty,arrOfMaps>::operator [](const std::basic_string<_Elem,_Traits,_Ax> &))[3]'
2> with
2> [
2> _Kty=std::string,
2> _Ty=int,
2> _Elem=char,
2> _Traits=std::char_traits<char>,
2> _Ax=std::allocator<char>
2> ]
2> c:\work\toot\tootcode\tootim\tools\doobim\doobim.cpp(95) : see reference to class template instantiation 'std::map<_Kty,_Ty>' being compiled
2> with
2> [
2> _Kty=std::string,
2> _Ty=arrOfMaps
2> ]
2>
2>Build FAILED.
2>
2>Time Elapsed 00:00:01.38
========== Build: 1 succeeded, 1 failed, 5 up-to-date, 0 skipped ==========
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知道如何让它工作?(我不想改变数据结构,这是一个map:string - > array of maps of)
您不能将C样式数组存储在容器中,因为它们不可分配; 你不能做这个:
int x[3] = { 0, 1, 2 };
int y[3] = { 3, 4, 5 };
x = y;
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但是容器需要能够分配/复制它们存储的元素.
考虑使用a std::vector或boost::array*而不是原始C数组.
std::array在最近的C++标准修订版中找到.