Linux内核链表实现的list_entry()中的(char*)强制转换

Question

这是宏定义:

/**
 * list_entry - get the struct for this entry
 * @ptr:    the &struct list_head pointer.
 * @type:   the type of the struct this is embedded in.
 * @member: the name of the list_struct within the struct.
 */
#define list_entry(ptr, type, member) \
    ((type *)((char *)(ptr)-(unsigned long)(&((type *)0)->member)))

我不明白为什么ptr被铸造(char *).我不能只是减去偏移的member距离ptr？像这样:

#define list_entry(ptr, type, member) \
        ((type *)((ptr)-(unsigned long)(&((type *)0)->member)))

谢谢!

Answer 1

不.指针算术相当于:

ptr[addend]

不

(ptr_type *)((unsigned long)&ptr + addend)

后者需要显式转换char *(因为这是内存单元)直接操作指针的值.