在换码代码中插入换行符Easy 68k(68000)

Question

我对组装很新,我正在尝试建立一个小程序.我无法弄清楚如何使用Easy68k在装配中插入换行符.例如,我开始编写基本的黑色插孔模拟器,我需要在问候第一个玩家后进行换行.我尝试将"\n"结合到变量声明中,但它只是打印出来就好像它是文本的一部分.

根据Easy 68K帮助I/O部分,我可以使用"LF EQU $ 0A新线(换行)"但我不知道如何实现它.

START   ORG        $400             ; Start of program area
    CLR.L      D0               ; Clear D0
    CLR.L      D1               ; Clear D1
    CLR.L      D2               ; Clear D2
    CLR.L      D3               ; Clear D3
    CLR.L      D4               ; Clear D4
    CLR.L      D5               ; Clear D5
    CLR.L      D6               ; Clear D6
    MOVE.L     playerTotal, D2  ; Store Player total in D1
    MOVE.L     card, D3         ; Store current card in D2
    MOVE.B     playerAce, D4    ; Store number of aces player has in D3
    MOVE       #14, D0      
    LEA        playerGreeting, A1   ; Load Player Greeting in A1
    TRAP       #15              ; Display Player Greeting
* insert line break     
    STOP       #$2700  ; Stop execution

        ORG         $1000   ;Start of data area
playerTotal DS.L        1       ; Save 1 byte of memory for playerTotal
dealerTotal DS.L        1       ; Save 1 byte of memory for dealerTotal
card        DC.L        5       ; Save 1 byte of memory for card dealt
keepPlaying DS.B        1       ; Save 1 byte of memory for Play again value
playerAce   DS.B        1       ; Save 1 byte of memory to track player Aces
playerGreeting  DC.B        'Hello Player 1!', 0    ; Message 

                LF        EQU       $0A
                END     START                  ; End of program and entry point

Answer 1

试试这个:

CR EQU $0D
LF EQU $0A
playerGreeting  DC.B        'Hello Player 1!',CR,LF,0    ; Message

这将在您的消息后插入回车符(CR)和换行符(LF).基本上它在null终止符(0)之前将两个附加字符添加到输出字符串.