PC.*_*PC. 1 java collections unique set hashset
JavaDoc将set定义为:
不包含重复元素的集合.更正式地说,集合不包含元素e1和e2对,因此e1.equals(e2)
为了验证相同,我创建了一个非常简单的程序:
import java.util.HashSet;
public class CheckHashSet {
public static void main(String[] args) {
HashSet<Employee> set = new HashSet<Employee>();
set.add(new Employee(10));
set.add(new Employee(10));
System.out.println(set.size());
System.out.println(new Employee(10).equals(new Employee(10)));
}
private static class Employee implements Comparable<Employee> {
private final int id;
public Employee(int id) {
this.id = id;
}
@Override
public int compareTo(Employee o) {
return this.id - o.id;
}
@Override
public boolean equals(Object obj) {
if(obj instanceof Employee) {
return compareTo((Employee)obj)==0;
}
return false;
}
}
}
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该程序的输出是
2
true
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这意味着new Employee(10).equals(new Employee(10))返回true,同时set.add(new Employee(10)); set.add(new Employee(10));将对象添加两次.
我的代码出了什么问题?
您的Employee类不会覆盖hashCode- 它需要这样做才能使任何基于散列的集合起作用.
例如:
@Override
public int hashCode() {
return id;
}
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