将"first,middle,middle,last"拆分为包含3个元素的数组(first,middle,last)

Question

我想将以下字符串拆分为三个元素:

first, middle, middle, middle, middle, last

结果将是:

splits[0] = "first"
splits[1] = "middle, middle, middle, middle"
splits[2] = "last"

我不知道这是否最好用正则表达式或字符串方法完成.

Answer 1

var s = "first, middle, middle, middle, middle, last";
var singleItems = s.Split(',').Select(x => x.Trim());
var splits = new []
             {
                 singleItems.Take(1).Single(),
                 singleItems.Skip(1).Take(singleItems.Count() - 2)
                                    .Aggregate("", (s1, s2) => s1 + s2 + ", ")
                                    .Trim(' ', ','),
                 singleItems.Skip(singleItems.Count() - 1).Single()
             };

另一种方法是:

var firstIndex = s.IndexOf(',');
var lastIndex = s.LastIndexOf(',');
var splits = new []
             {
                 s.Substring(0, firstIndex),
                 s.Substring(firstIndex + 2, lastIndex - (firstIndex + 2)),
                 s.Substring(lastIndex + 2)
             };

我认为第二种解决方案更清洁,更容易理解.但它的缺点是第一个和最后一个逗号必须后跟一个空格.第一个版本不存在此要求.