迭代两个继承类的两个列表(相同的基类)

Question

我有两个清单.两个列表的类型都继承自相同的基类型.我想迭代它们并执行仅使用基类功能的操作,而不必依次使用两个基本相同的foreach循环.

我无法将列表复制到另一个列表或类似的东西,因为我需要在操作完成后单独使用原始表单中的列表.

有没有办法在不编写函数的情况下执行此操作？

class Program
{
    static void Main(string[] args)
    {
        // I have two lists of inherited classes
        List<Babby1> list1 = returnBabby1();
        List<Babby2> list2 = returnBabby2();

        // I want to iterate through both, and do the same thing, which is a part
        // of the base class functionality.
        // Basically I want this to be a single foreach loop.
        foreach (Babby1 item in list1)
            item.var = 50;

        foreach (Babby2 item in list2)
            item.var = 50;

        // I have to send them as separate lists, the type being the original (inherited) class
        sendBabby1(list1);
        sendBabby2(list2);
    }

    static void sendBabby1(List<Babby1> list)
    {
    }

    static void sendBabby2(List<Babby2> list)
    {
    }

    static List<Babby1> returnBabby1()
    {
        return new List<Babby1>();
    }

    static List<Babby2> returnBabby2()
    {
        return new List<Babby2>();
    }
}

class Base
{
    public int var;
}

class Babby1 : Base
{
    public int var1;
}

class Babby2 : Base
{
    public int var2;
}

Answer 1

这应该是诀窍......

foreach (var item in list1.Concat<Base>(list2))
{
    // Do your thing
}

编辑:我改为Union,Concat因为我认为它可能更合适.