Dav*_*ave 1 php mysql pdo prepared-statement
我有一小段PHP代码:
$stm = $db->prepare($sql);
$result = $stm->execute($params);
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$ params如下
array(1) {
[0]=>
string(3) "why"
}
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但是,发送到MySQL的$ sql仍然包含一个根据MySQL日志的问号:
1 Query SELECT a.* FROM article a
LEFT JOIN article_links al on a.id = al.from_article_id
WHERE al.to_article = '?'
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是否有其他东西我缺少替代?
您不需要在问号周围加上单引号:
SELECT a.* FROM article a
LEFT JOIN article_links al on a.id = al.from_article_id
WHERE al.to_article = ?;
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