我有两个列表见下面.....结果回来是空的
List<Pay>olist = new List<Pay>();
List<Pay> nlist = new List<Pay>();
Pay oldpay = new Pay()
{
EventId = 1,
Number = 123,
Amount = 1
};
olist.Add(oldpay);
Pay newpay = new Pay ()
{
EventId = 1,
Number = 123,
Amount = 100
};
nlist.Add(newpay);
var Result = nlist.Intersect(olist);
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任何线索为什么?
Tho*_*que 25
您需要覆盖类中的Equals和GetHashCode方法Pay,否则Intersect不知道2个实例何时被视为相等.怎么能猜到它EventId决定了平等呢?oldPay并且newPay是不同的实例,因此默认情况下它们不被视为相等.
您可以Pay像这样覆盖方法:
public override int GetHashCode()
{
return this.EventId;
}
public override bool Equals(object other)
{
if (other is Pay)
return ((Pay)other).EventId == this.EventId;
return false;
}
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另一种选择是实现IEqualityComparer<Pay>并将其作为参数传递给Intersect:
public class PayComparer : IEqualityComparer<Pay>
{
public bool Equals(Pay x, Pay y)
{
if (x == y) // same instance or both null
return true;
if (x == null || y == null) // either one is null but not both
return false;
return x.EventId == y.EventId;
}
public int GetHashCode(Pay pay)
{
return pay != null ? pay.EventId : 0;
}
}
...
var Result = nlist.Intersect(olist, new PayComparer());
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