我有逻辑问题吗？

Question

contact entry = {"", "", "", ""};

while (choice == 1 || 2 || 3 || 4){  
    if (choice == 1){
        printf ("First name: \n");    
        fgets(entry.firstname, sizeof(entry.firstname),stdin); 
        break;
    }
    else if(choice == 2){
        printf ("Last name: \n");     
        fgets(entry.lastname, sizeof(entry.lastname),stdin); 
        break;
    }
    else if(choice == 3){
        printf ("Address: \n");   
        fgets(entry.address, sizeof(entry.address),stdin); 
        break;
    }
    else if (choice == 4){
        printf ("Phone number: \n");      
        fgets(entry.phone, sizeof(entry.phone),stdin); 
        break;
    }
    else{
        printf("Exiting");
        return 0;
    }
}

fwrite (&entry, sizeof (contact), 1, pFile);
fclose(pFile);

这是我的代码.它似乎很简单,如果按1,2,3或4,我跟踪它.所以它知道if,否则if,否则它会去,但它似乎很快就退出,并且没有写出我想要的文件.这里有任何明显的错误吗？提前致谢.

编辑1:

我改变了(choice> = 1 && choice <= 4){to while(choice> = 1 && choice <= 4){,但我仍然遇到没有写入文件的问题.pFile = fopen("C:\ contacts.txt","w +"); 是我理解的正确方法.

Answer 1

更改:

while (choice == 1 || 2 || 3 || 4){  

至:

while (choice == 1 || choice == 2 || choice == 3 || choice == 4){  

或者更简洁:

while (choice >= 1 && choice <= 4){