我有以下MySQL:
select `car`.`ID` AS `ID`,
`title`,`text`
from `car`
LEFT JOIN `truck` as bigcar ON bigcar.`ID` = `car`.`truckID`
WHERE `ID` ='1';
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出于某种原因,我得到了
where子句中的列'ID'不明确
出于复杂的代码原因,我不会将别名重命名为其他内容(例如ID2)
这不应该起作用吗?
您需要id在where子句中指定要用于的表.否则,查询将不知道要使用哪一个,因为在两个表中具有相同的列名
SELECT
`car`.`ID` AS `ID`, `title`,`text`
FROM `car`
LEFT JOIN `truck` as bigcar ON bigcar.`ID` = `car`.`truckID`
WHERE `car`.`ID` ='1';
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或者如果您想要bigcarID,您将不得不使用:
WHERE `bigcar`.`ID` ='1'; // not truck but bigcar which is the alias you created
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