SELECT * FROM Employee
(
SELECT eid FROM Assignment
GROUP BY eid
HAVING SUM(hours_per_week) > 40
)
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这是我的代码,用于查找超过40的hours_per_week.子查询返回超过40小时的人的eid.我的问题是如何使用从子查询中获得的eid显示Employee中的所有人员.在哪里?还是加入?
使用 WHERE ... IN (SELECT ...)
SELECT col1, col2, ..., coln
FROM Employee
WHERE eid IN
(
SELECT eid FROM Assignment
GROUP BY eid
HAVING SUM(hours_per_week) > 40
)
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