如何播放AudioRecord有一些延迟

Question

我正在实现一个应用程序,它将重复我告诉它的所有内容.我需要的是播放我在缓冲区录制的声音只是延迟了一秒钟因此我会自己听,但延迟1秒

这是我的Recorder类的run方法

public void run()
    {           
        AudioRecord recorder = null;
        int ix = 0;
        buffers = new byte[256][160];

        try
        {
            int N = AudioRecord.getMinBufferSize(44100,AudioFormat.CHANNEL_IN_STEREO,AudioFormat.ENCODING_PCM_16BIT);
            recorder = new AudioRecord(AudioSource.MIC, 44100, AudioFormat.CHANNEL_IN_STEREO, AudioFormat.ENCODING_PCM_16BIT, N*10);               
            recorder.startRecording();
            Timer t = new Timer();              
            SeekBar barra = (SeekBar)findViewById(R.id.barraDelay);
            t.schedule(r = new Reproductor(), barra.getProgress());           

            while(!stopped)
            {                   
                byte[] buffer = buffers[ix++ % buffers.length];                 
                N = recorder.read(buffer,0,buffer.length);                  
            }
        }
        catch(Throwable x)
        {               
        }

        finally
        { 
            recorder.stop();
            recorder.release();
            recorder = null;                        
        }

这是我的玩家之一:

public void run() {
        reproducir = true;

        AudioTrack track = null;            
        int jx = 0;

        try
        {
            int N = AudioRecord.getMinBufferSize(44100,AudioFormat.CHANNEL_IN_STEREO,AudioFormat.ENCODING_PCM_16BIT);               
            track = new AudioTrack(AudioManager.STREAM_MUSIC, 44100, 
                    AudioFormat.CHANNEL_OUT_STEREO, AudioFormat.ENCODING_PCM_16BIT, N*10, AudioTrack.MODE_STREAM);              
            track.play();
            /*
             * Loops until something outside of this thread stops it.
             * Reads the data from the recorder and writes it to the audio track for playback.
             */
            while(reproducir)
            {                   
                byte[] buffer = buffers[jx++ % buffers.length];                 
                track.write(buffer, 0, buffer.length);
            }
        }
        catch(Throwable x)
        {               
        }
        /*
         * Frees the thread's resources after the loop completes so that it can be run again
         */
        finally
        {               
            track.stop();
            track.release();
            track = null;               
        }

    }

Reproductor是一个扩展TimerTask并实现"run"方法的内部类.

非常感谢!

Answer 1

至少你应该改变你的播放器的以下行

int N = AudioRecord.getMinBufferSize(44100,AudioFormat.CHANNEL_IN_STEREO,AudioFormat.ENCODING_PCM_16BIT);               

到

int N = AudioTrack.getMinBufferSize(44100, AudioFormat.CHANNEL_OUT_STEREO, AudioFormat.ENCODING_PCM_16BIT);

因为 API 要求这样做（尽管常数值是相同的）。

但这只是一个边缘点。主要的一点是，您并没有真正提出解决问题的方法，而只是提出了两种通用方法。

可行解决方案的核心是使用大小为 1 秒的环形缓冲区，并AudioTrack在将新数据写入同一块之前读取AudioRecord其中的一个块，两者都以相同的采样率。

我建议在单个线程内执行此操作。