如何将Python程序移植到Ruby

Question

我正在尝试将Python程序移植到Ruby,但我完全不了解Python.

你能给我一些建议吗？

我想运行sampletrain方法.但是,我不明白为什么features=self.getfeatures(item)可用.getfeatures只是一个实例变量,不是吗？它似乎被用作一种方法.

docclass.py:

class classifier:
  def __init__(self,getfeatures,filename=None):
    # Counts of feature/category combinations
    self.fc={}
    # Counts of documents in each category
    self.cc={}
    self.getfeatures=getfeatures

  def train(self,item,cat):
    features=self.getfeatures(item)
    # Increment the count for every feature with this category
    for f in features:
      self.incf(f,cat)

    # Increment the count for this category
    self.incc(cat)
    self.con.commit()

  def sampletrain(cl):
    cl.train('Nobody owns the water.','good')
    cl.train('the quick rabbit jumps fences','good')
    cl.train('buy pharmaceuticals now','bad')
    cl.train('make quick money at the online casino','bad')
    cl.train('the quick brown fox jumps','good')

Answer 1

在Python中,因为方法调用的括号不是可选的,所以可以区分对方法的引用和方法的调用.即

def example():
    pass

x = example # x is now a reference to the example 
            # method. no invocation takes place
            # but later the method can be called as
            # x()

与

x = example() # calls example and assigns the return value to x

因为方法调用的括号在Ruby中是可选的,所以你需要使用一些额外的代码,例如x = method(:example)并x.call实现相同的功能.