在webmock中多次调用具有不同结果的同一端点?

Pet*_*ter 13 ruby rspec mocking webmock

我有一些看起来像这样的代码:

while response.droplet.status != env["user_droplet_desired_state"] do
   sleep 2
   response = ocean.droplet.show env["droplet_id"]
   say ".", nil, false
end
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您可以将应用程序设置为等到服务器处于某种状态(例如,重新启动它,然后再观察它直到它再次处于活动状态)

但是,我在测试中使用webmock,我无法找到第二次给出不同响应的方法.

例如,代码如下:

  stub_request(:get, "https://api.digitalocean.com/v2/droplets/6918990?per_page=200").
     with(:headers => {'Accept'=>'*/*', 'Accept-Encoding'=>'gzip;q=1.0,deflate;q=0.6,identity;q=0.3', 'Authorization'=>'Bearer foo', 'Content-Type'=>'application/json', 'User-Agent'=>'Faraday v0.9.2'}).
     to_return(:status => 200, :body => fixture('show_droplet_inactive'), :headers => {})

  stub_request(:get, "https://api.digitalocean.com/v2/droplets/6918990?per_page=200").
     with(:headers => {'Accept'=>'*/*', 'Accept-Encoding'=>'gzip;q=1.0,deflate;q=0.6,identity;q=0.3', 'Authorization'=>'Bearer foo', 'Content-Type'=>'application/json', 'User-Agent'=>'Faraday v0.9.2'}).
     to_return(:status => 200, :body => fixture('show_droplet'), :headers => {})
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这个想法是"第一次标记为无效,所以循环经历一次,然后标记为活动"

文档说存根只是作为"找到的最后一个将工作":

始终应用与请求匹配的最后声明的存根,即:

stub_request(:get,"www.example.com").to_return(:body =>"abc")

stub_request(:get,"www.example.com").to_return(:body =>"def")

Net :: HTTP.get('www.example.com','/')#====>"def"

是否可以在webmock中为具有不同结果的同一端点建模多个调用?

wom*_*ble 20

如果你将一个哈希数组传递给#to_return它,它将每次响应下一个响应(然后只是一遍又一遍地返回最后一个).例如:

require 'webmock/rspec'
require 'uri'

describe "something" do
   it "happens" do
      stub_request(:get, 'example.com/blah').
        to_return({status: 200, body: 'ohai'}, {status: 200, body: 'there'})

      puts Net::HTTP.get(URI('http://example.com/blah'))
      puts Net::HTTP.get(URI('http://example.com/blah'))
      puts Net::HTTP.get(URI('http://example.com/blah'))
      puts Net::HTTP.get(URI('http://example.com/blah'))
   end
end
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运行时rspec <file>,将打印:

ohai
there
there
there
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