当它包含&时,您将如何创建有效的URL字符串

Rya*_*n S 1 html

以此为例: <a href="manageCart.php?action=remove&id=49">

验证后,您将获得以下结果:

Line 26, Column 802: & did not start a character reference. (& probably should have been escaped as &amp;.)

但这不是内容,所以&是必要的.如何使它成为有效的HTML?

Jos*_*kle 6

<a href="manageCart.php?action=remove&amp;id=49">
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使用 &amp;