Abh*_*ary 3 java comparator treeset
从提供的输入字符串:
{"200,400,7,1","100,0,1,1","200,200,3,1","0,400,11,1","407,308,5,1","100,600,9,1" },
我在TreeSet中添加相同的内容并希望它按第3个元素顺序排序,因此预期的输出将是:
(100,0,1,1)(200,200,3,1)(407,308,5,1)(200,400,7,1)(100,600,9,1)(0,400,11,1)
但我的实际输出是:
(100,0,1,1)(0,400,11,1)(200,200,3,1)(407,308,5,1)(200,400,7,1)(100,600,9,1)
但由于11的字符串比较小于9,但就整数而言,11> 9.我的预期产量变得不同了.建议我解决同样的问题.
import java.util.Comparator;
import java.util.TreeSet;
public class TreeSetComparator {
public static void main(String[] args) {
Comparator<String> comparator = new Comparator<String>() {
@Override
public int compare(String a, String b) {
String aStr = a;
String bStr = b;
String[] splitA = aStr.split(",");
String[] splitB = bStr.split(",");
return splitA[2].compareTo(splitB[2]);
}
};
String[] arr = { "200,400,7,1", "100,0,1,1", "200,200,3,1",
"0,400,11,1", "407,308,5,1", "100,600,9,1" };
TreeSet<String> ts = new TreeSet<String>(comparator);
for (String str : arr) {
ts.add(str);
}
for (String element : ts)
System.out.print(element + " ");
}
}
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Bar*_*ers 11
你按照字典顺序排序("123"之前是"20"),你需要做的是将它们转换为整数,然后比较它们:
不:
return splitA[2].compareTo(splitB[2]);
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但:
return Integer.valueOf(splitA[2]).compareTo(Integer.valueOf(splitB[2]));
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然而,稍微更清洁的方式是创建自定义对象保持这4个不同的值,然后创建一个Comparator用于比较3 次这样的对象的值:
下列:
public class Main {
public static void main (String[] args) {
Comparator<CustomObject> sortOn3rdValue = new Comparator<CustomObject>() {
@Override
public int compare(CustomObject o1, CustomObject o2) {
return o1.v3 < o2.v3 ? -1 : o1.v3 > o2.v3 ? 1 : 0;
}
};
Set<CustomObject> objects = new TreeSet<CustomObject>(sortOn3rdValue);
String[] arr = { "200,400,7,1", "100,0,1,1", "200,200,3,1", "0,400,11,1", "407,308,5,1", "100,600,9,1" };
for(String a : arr) {
objects.add(new CustomObject(a.split(",")));
}
for(CustomObject co : objects) {
System.out.println(co);
}
}
}
class CustomObject {
final int v1, v2, v3, v4;
CustomObject(String[] strValues) {
// assume strValues.lenght == 4
v1 = Integer.valueOf(strValues[0]);
v2 = Integer.valueOf(strValues[1]);
v3 = Integer.valueOf(strValues[2]);
v4 = Integer.valueOf(strValues[3]);
}
@Override
public String toString() {
return String.format("(%d,%d,%d,%d)", v1, v2, v3, v4);
}
}
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会打印:
(100,0,1,1) (200,200,3,1) (407,308,5,1) (200,400,7,1) (100,600,9,1) (0,400,11,1)
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