`XmlConvert.ToDateTime(String)` 和 `XmlConvert.ToString(DateTime)` 输出不一致

DxC*_*xCK 3 .net c# xml timezone

我有问题XmlConvertDateTime

当使用XmlConvert.ToDateTime(String)then convert将某些字符串转换DateTime回字符串时XmlConvert.ToString(DateTime),结果字符串与原始字符串不同,并且取决于本地时区。

以下控制台应用程序代码演示了该问题:

using System;
using System.Xml;

namespace DateTimeXmlConvertTest
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("Original Value\t\t\t\tNew Value");
            Console.WriteLine("--------------\t\t\t\t---------");

            for (int i = -12; i <= 12; i++)
            {
                string sign = i < 0 ? "" : "+";

                string originalString = "2011-10-01T01:18:54.6652000" + sign + i.ToString("D2") + ":00";
                DateTime now = XmlConvert.ToDateTime(originalString);
                string newValue = XmlConvert.ToString(now);
                Console.WriteLine(originalString + "\t" + newValue);
            }
        }
    }
}
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在我的 PC(Windows 7 x64,TimeZone UTC+02:00 with Daylight)上运行这个程序时,我有以下输出:

Original Value                          New Value
--------------                          ---------
2011-10-01T01:18:54.6652000-12:00       2011-10-01T16:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-11:00       2011-10-01T15:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-10:00       2011-10-01T14:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-09:00       2011-10-01T13:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-08:00       2011-10-01T12:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-07:00       2011-10-01T11:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-06:00       2011-10-01T10:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-05:00       2011-10-01T09:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-04:00       2011-10-01T08:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-03:00       2011-10-01T07:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-02:00       2011-10-01T06:18:54.6652000+03:00
2011-10-01T01:18:54.6652000-01:00       2011-10-01T05:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+00:00       2011-10-01T04:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+01:00       2011-10-01T03:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+02:00       2011-10-01T02:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+03:00       2011-10-01T01:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+04:00       2011-10-01T00:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+05:00       2011-09-30T23:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+06:00       2011-09-30T22:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+07:00       2011-09-30T21:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+08:00       2011-09-30T20:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+09:00       2011-09-30T19:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+10:00       2011-09-30T18:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+11:00       2011-09-30T17:18:54.6652000+03:00
2011-10-01T01:18:54.6652000+12:00       2011-09-30T16:18:54.6652000+03:00
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当转换为不同的字符串然后从它转换为不同的字符串时,怎么可能?

在这种情况下,有没有办法让它输出原始字符串?

谢谢。

Asb*_*erg 5

首先,XmlConvert.ToDateTime(String)重载已过时。该文档明确指定您应该使用它XmlConvert.ToDateTime(String, XmlDateTimeSerializationMode)。有了它,您就可以指定XmlDateTimeSerializationMode,其记录如下:

XmlDateTimeSerializationMode 值之一,用于指定日期是应转换为本地时间还是保留为协调世界时 (UTC)(如果它是 UTC 日期)。

当您拥有 的实例时DateTime,它的构造方式(例如,其时区)将丢失。时区将从原始字符串正确解析并转换为 UTC 或本地时间,但转换的内容在此过程中丢失。

如果要保留时区偏移量,请使用DateTimeOffset该类。它的行为类似于DateTime,但保留了创建它的时区偏移量。XmlConvert有一种ToDateTimeOffset方法可以完全满足您的要求。这是一个工作示例:

Console.WriteLine("{0,33}\t{1,33}", "Original Value", "New Value");
Console.WriteLine("{0}\t{0}", new String('-', 33));

for (int i = -12; i <= 12; i++)
{
    string sign = i < 0 ? "" : "+";
    string originalString = String.Format(
        "2011-10-01T01:18:54.6652123{0}{1:D2}:00", sign, i);
    DateTimeOffset dateTime = XmlConvert.ToDateTimeOffset(originalString);
    string newString = XmlConvert.ToString(dateTime);
    Console.WriteLine("{0}\t{1}", originalString, newString);
}
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您现在唯一的问题是+00:00将被序列化为Z,如果您newString自己格式化可以避免这种情况,如下所示:

string newString = String.Format("{0:yyyy-MM-ddTHH:mm:ss.fffffffzzz}", dateTime);
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