我在android工作.我正在设计一个程序来将文件上传到http服务器.
但每当我运行这个程序并选择一个稍大一点的文件时,这将产生以下错误.
java.lang.OutOfMemoryError
at java.io.ByteArrayOutputStream.expand(ByteArrayOutputStream.java:93)
at java.io.ByteArrayOutputStream.write(ByteArrayOutputStream.java:218)
ERROR/AndroidRuntime(557): at
org.apache.harmony.luni.internal.net.www.protocol.http.HttpURLConnectionImpl$DefaultHttpOut
putStream.write(HttpURLConnectionImpl.java:750)
10-15 03:08:32.113: ERROR/AndroidRuntime(557): at
java.io.DataOutputStream.write(DataOutputStream.java:101)
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这是我上传的文件: -
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName = "/mnt/sdcard/kuntal.PNG";
Log.v("File upload",""+Environment.getExternalStorageDirectory().getAbsolutePath());
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
Log.v(TAG,"url= ");
String urlString = "http://192.168.1.126/MusicApplication/uploadmusic.php?title="+title_by_artist+"&category="+category_of_song+"&filename="+filename+"&price="+price_of_song+"&artist="+HomePageActivity.username;
Log.v(TAG,"url= "+urlString);
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(existingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
dos.flush();
dos.close();
Toast.makeText(this, "File Successfully Uploaded", Toast.LENGTH_SHORT).show();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
**and this is my php file for upload:-**
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
chmod ("Songs/".basename( $_FILES['uploadedfile']['name']), 0644);
}
else
{
echo "filename: " . basename( $_FILES['uploadedfile']['name']);
echo "target_path: " .$target_path;
}
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请帮我,我该怎么做上传像mp3文件更大的文件.先感谢您...
我自己解决了我的问题.
这是我在我的java文件中所做的更改: -
buffer = new byte[bufferSize];
bufferSize = Math.min(bytesAvailable, maxBufferSize);
byte byt[]=new byte[bufferSize];
fileInputStream.read(byt);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
dos.write(buffer, 0, bufferSize);
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在我的问题中,以下内容code被替换: -
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
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