将Basler图像转换为OpenCV

Question

我正在尝试将从Basler相机捕获的帧转换为OpenCV的Mat格式.Basler API文档中没有很多信息,但这些是Basler示例中的两行,在确定输出格式时应该有用:

// Get the pointer to the image buffer
const uint8_t *pImageBuffer = (uint8_t *) Result.Buffer();
cout << "Gray value of first pixel: " << (uint32_t) pImageBuffer[0] << endl << endl;

我知道图像格式是什么(目前设置为单声道8位),并尝试过:

img = cv::Mat(964, 1294, CV_8UC1, &pImageBuffer);
img = cv::Mat(964, 1294, CV_8UC1, Result.Buffer());

两者都不奏效.任何建议/建议将不胜感激,谢谢!

编辑:我可以通过以下方式访问Basler图像中的像素:

for (int i=0; i<1294*964; i++)
  (uint8_t) pImageBuffer[i];

如果这有助于将其转换为OpenCV的Mat格式.

Answer 1

您正在创建cv图像以使用相机的内存 - 而不是拥有自己内存的图像.问题可能是相机正在锁定该指针 - 或者可能希望在每个新图像上重新分配和移动它

尝试在没有最后一个参数的情况下创建图像,然后使用memcpy()将像素数据从相机复制到图像.

// Danger! Result.Buffer() may be changed by the Basler driver without your knowing          
const uint8_t *pImageBuffer = (uint8_t *) Result.Buffer();  

// This is using memory that you have no control over - inside the Result object
img = cv::Mat(964, 1294, CV_8UC1, &pImageBuffer);

// Instead do this
img = cv::Mat(964, 1294, CV_8UC1); // manages it's own memory

// copies from Result.Buffer into img 
memcpy(img.ptr(),Result.Buffer(),1294*964); 

// edit: cvImage stores it's rows aligned on a 4byte boundary
// so if the source data isn't aligned you will have to do
for (int irow=0;irow<964;irow++) {
     memcpy(img.ptr(irow),Result.Buffer()+(irow*1294),1294);
 }