有点像连接但不完全

1 python concatenation

for seqA in poolA:
    print seqA + ":",
    for i in seqA:
        print complements[i],
    print
Run Code Online (Sandbox Code Playgroud)

complements是一个dict,poolA是一个list.

当我print complements[i]中间有空格时,如何删除这些空格?

Pet*_*rin 5

加入项目并打印结果字符串.

print ''.join(str(complements[i]) for i in seqA)
Run Code Online (Sandbox Code Playgroud)