如何使用jQuery将查询字符串传递给Ajax调用？

Question

如何使用jQuery将查询字符串传递给Ajax调用？

Zey*_*nel 5 javascript jquery query-string

我items从数据库中取出并在for循环中显示它们.我使用jQuery来隐藏其中一行.现在我需要获取main_id隐藏的行并传递给它$.ajax.在Paul建议使用的原始问题中,alert(this.attr("title"));但是这一行会停止执行$.ajax调用,并且不会执行调用.当我注释掉警报时alert(this.attr("title"));,ajax调用就会通过.在这种情况下,我得到一个错误,因为display_false()处理程序中的函数没有得到的值main_id.

这是"隐藏"链接的html title=%s.

<a class="false" title=%s href="/useradminpage?main_id=%s&display=false"><span class="small">(hide)</span></a>

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所以我需要main_id在执行ajax调用时将存储的值传递alert(this.attr("title"));给函数display_false().

我怎样才能做到这一点？

相关代码如下:

剧本

        self.response.out.write("""
<html>
<head>
<link type="text/css" rel="stylesheet" href="/stylesheets/main.css" /> 
<title>User Admin Page</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<script>

$(document).ready(function() {

    alert("1 - document ready is called")
    $("a.false").click(function(e) {
        $(this).closest("tr.hide").hide("slow");
        e.preventDefault();
        alert("2 - row is hidden")
    });

    $("a.false").click(function() {
        alert("3 - ajax")
        //the following alert stops the ajax call from executing
        alert(this.attr("title"));

        $.ajax({
            url: "/useradminpage?main_id=%s&display=false",
            data: {main_id: "title"}
            success: function(data) {
            display_false()
            alert(4 - "returned");
            }
        });
    });
});


</script>
</head>
<body>
""")

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HTML

#-----------main table------------#
            main_id = self.request.get("main_id")

            self.response.out.write("""<table class="mytable">
            <tr class="head">
            <th  width="80%">links</th><th>edit tags</th>
            </tr>    
            """)        

            query = Main.all()
            query.filter("owner", user)
            query.filter("display", True)
            query.order("-date")
            cursor = self.request.get("cursor")
            if cursor: query.with_cursor(cursor)
            e = query.fetch(100)
            cursor = query.cursor()

            for item in e:
                main_id = item.key().id()
                self.response.out.write("""
                <tr class="hide">
                <td><a href="%s" target="_blank">%s</a><span class=small> (%s) </span><br />
                <span class=small>%s</span>
                <a href="/edit?main_id=%s"><span class="small">(edit)</span></a>
                <a class="false" title=%s href="/useradminpage?main_id=%s&display=false"><span class="small">(hide)</span></a>
                <a href="/comment?main_id=%s"><span class="small">(comments)</span></a></td>
                <td><a href="/tc?url=%s&main_id=%s&user_tag_list=%s" title="edit tags">%s</a>
                </td>
                </tr>
                """ % tuple([item.url, item.title, urlparse(item.url).netloc,
                f1.truncate_at_space(item.pitch), main_id, 

                main_id,

                main_id, main_id,
                item.url, main_id, (", ".join(item.tag_list)),
                (", ".join(item.tag_list)),]))

            self.response.out.write("""</tbody></table>""")    

            display = self.request.get("display")

            def display_false():
                if display == "false":
                    main_id = self.request.get("main_id")
                    #I tried to get the "title" but this does not work
                    #main_id = self.request.get("title")
                    k = Main.get_by_id(int(main_id))
                    k.display = False                    
                    k.put()

            display_false()    
            ...

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更新

根据James Montagne的回答(稍作修改)更新了代码.现在,由于某种原因,文件就绪没有加载,并且隐藏行的调用不起作用,但更新数据库的ajax调用正在运行.我究竟做错了什么？

<script>

$(document).ready(function() {

    alert("1 - document ready is called")
    $("a.false").click(function(e) {
        $(this).closest("tr.hide").hide("slow");
        var main_id = this.attr("title");
        var display = "false";
        e.preventDefault();
        alert("2 - row is hidden")
    });

    $("a.false").click(function() {
        alert("3 - ajax");

        $.ajax({
            url: "/useradminpage?main_id=%s&display=false",
            data: {main_id: "main_id", display: "display")},
            success: function(data) {
            display_false()
            alert(4 - "returned");
            }
        });
    });
});


</script>

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Answer 1

Jam*_*gne 6

您无需提醒该值,您需要传递它.目前您正在传递字符串title.

    $.ajax({
        url: "/useradminpage?main_id=%s&display=false",
        data: {main_id: this.attr("title")}
        success: function(data) {
        display_false()
        alert(4 - "returned");
        }
    });

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