如果我以这种方式生成 10 个随机数,它会起作用(它会产生不同的值)
fn main() {
let seed = std::time::SystemTime::now()
.duration_since(std::time::UNIX_EPOCH)
.expect("system time cannot be before unix epoch")
.as_millis() as u64;
let mut rng = oorandom::Rand32::new(seed);
for _ in 0..10 {
println!("Your random number is: {}", &rng.rand_range(0..4));
}
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但如果我将它们分解到一个结构中,生成的值总是相同的:
use oorandom::{self, Rand32};
struct Util {
rng: Rand32,
}
impl Util {
pub fn new() -> Self {
let seed = std::time::SystemTime::now()
.duration_since(std::time::UNIX_EPOCH)
.unwrap()
.as_millis() as u64;
println!("new color util {}", seed);
let rng = Rand32::new(seed);
Util { rng }
}
pub fn get_random(&self) -> u32 {
let mut rng = self.rng;
let random_number = rng.rand_range(0..4);
random_number
}
}
fn main() {
let util = Util::new();
for _ in 0..10 {
println!("Your random number is: {}", util.get_random());
}
}
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这两种使用 API 的方法有什么区别get_random,为什么当我放入rng结构时它会中断?
这不起作用,因为您正在复制rng结构,然后对其进行变异(注册您已采样了一个数字):
impl Util {
pub fn get_random(&self) -> u32 {
let mut rng = self.rng; // <-- here you copy `rng`,
// creating a new value, unrelated with `self.rng`
let random_number = rng.rand_range(0..4); // <-- here you mutate `rng`,
random_number // but leave `self.rng` untouched
}
}
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相反,您必须采用可变借用才能就地self变异:rng
impl Util {
pub fn get_random(&mut self) -> u32 {
// +++ `mut` has been added, to allow mutation of `self`
let rng = &mut self.rng; // this does not copy `self.rng`
let random_number = rng.rand_range(0..4);
random_number
}
}
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或者,更短的时间
impl Util {
pub fn get_random(&mut self) -> u32 {
let random_number = self.rng.rand_range(0..4);
random_number
}
}
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甚至
impl Util {
pub fn get_random(&mut self) -> u32 {
self.rng.rand_range(0..4)
}
}
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