Abb*_*bas 10 .net datatable json.net deserialization
有谁知道如何从asp.net将json字符串转换为DataTable?我开始了解Deserialize,它需要类,我只想要返回数据表.谁能告诉我如何将其转换为数据表?
Fra*_*ank 19
假设您的JSON字符串是对象列表,每个对象将对应于DataTable中的一行,即:
public DataTable DerializeDataTable()
{
const string json = @"[{""Name"":""AAA"",""Age"":""22"",""Job"":""PPP""},"
+ @"{""Name"":""BBB"",""Age"":""25"",""Job"":""QQQ""},"
+ @"{""Name"":""CCC"",""Age"":""38"",""Job"":""RRR""}]";
var table = JsonConvert.DeserializeObject<DataTable>(json);
return table;
}
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这需要Json.NET框架.
如果您的JSON结构不同,请发布它.最好的祝福.
小智 8
using Newtonsoft.Json;
string json = "[{"clientID":"1788","projectID":"19"},{"clientID":"1789","projectID":"24"},{"clientID":"1790","projectID":"24"},{"clientID":"1790","projectID":"23"},{"clientID":"1790","projectID":"21"}]";
DataTable tester = (DataTable) JsonConvert.DeserializeObject(json, (typeof(DataTable)));
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上述方法的代码
public object Deserialize(string jsonText, Type valueType)
{
try
{
Newtonsoft.Json.JsonSerializer json = new Newtonsoft.Json.JsonSerializer();
json.NullValueHandling = Newtonsoft.Json.NullValueHandling.Ignore;
json.ObjectCreationHandling = Newtonsoft.Json.ObjectCreationHandling.Replace;
json.MissingMemberHandling = Newtonsoft.Json.MissingMemberHandling.Ignore;
json.ReferenceLoopHandling = Newtonsoft.Json.ReferenceLoopHandling.Ignore;
StringReader sr = new StringReader(jsonText);
Newtonsoft.Json.JsonTextReader reader = new JsonTextReader(sr);
object result = json.Deserialize(reader, valueType);
reader.Close();
return result;
}
catch (Exception ex)
{
throw ex;
}
}
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将jsonstring反序列化为某个类
List<User> UserList = JsonConvert.DeserializeObject<User>(jsonString);
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将以下扩展方法写入您的项目
public static DataTable ToDataTable<T>(this IList<T> data)
{
PropertyDescriptorCollection props =
TypeDescriptor.GetProperties(typeof(T));
DataTable table = new DataTable();
for(int i = 0 ; i < props.Count ; i++)
{
PropertyDescriptor prop = props[i];
table.Columns.Add(prop.Name, prop.PropertyType);
}
object[] values = new object[props.Count];
foreach (T item in data)
{
for (int i = 0; i < values.Length; i++)
{
values[i] = props[i].GetValue(item);
}
table.Rows.Add(values);
}
return table;
}
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调用扩展方法就好
UserList.ToDataTable<User>();
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