生成具有特定开始和结束日期的时间序列

Question

我想生成一个包含该范围内所有业务日期的时间序列:

startDate = "1990-01-01"
endDate = "1990-12-31"

例如"1990-01-01","1990-01-02",......

Answer 1

@csgillespie:chron提供功能is.weekend:

days = seq(as.Date("1990-01-01"), as.Date("1990-12-31"), by="1 day")
library(chron)
weekDays = days[!is.weekend(days)]

## let's check the result with the function weekdays
weekdays(weekDays)

此外,您可以在不chron使用的情况下获得相同的结果format:

isWeekend <- function(x) {format(x, '%w') %in% c(0, 6)}
weekDays2 = days[!isWeekend(days)]

Answer 2

您只需使用该seq命令即可.例如,

##Specify you want 10 dates starting on 1990-01-01
R> seq(as.Date("1990-01-01"), length.out=10, by="1 day")
 [1] "1990-01-01" "1990-01-02" "1990-01-03" "1990-01-04" "1990-01-05"
 [6] "1990-01-06" "1990-01-07" "1990-01-08" "1990-01-09" "1990-01-10"

要么

##Specify the start and end with increment
R> seq(as.Date("1990-01-01"), as.Date("1990-01-10"), by="1 day")
 [1] "1990-01-01" "1990-01-02" "1990-01-03" "1990-01-04" "1990-01-05"
 [6] "1990-01-06" "1990-01-07" "1990-01-08" "1990-01-09" "1990-01-10"

要获得工作日,您可以使用该chron库:

days = seq(as.Date("1990-01-01"), as.Date("1990-12-31"), by="1 day")
library(chron)
weekDays = days[!is.weekend(days)]