Tom*_*man 32 sql sql-server join inner-join
我有以下查询:
SELECT TOP 25 CLIENT_ID_MD5, COUNT(CLIENT_ID_MD5) TOTAL
FROM dbo.amazonlogs
GROUP BY CLIENT_ID_MD5
ORDER BY COUNT(*) DESC;
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哪个回报:
283fe255cbc25c804eb0c05f84ee5d52 864458
879100cf8aa8b993a8c53f0137a3a176 126122
06c181de7f35ee039fec84579e82883d 88719
69ffb6c6fd5f52de0d5535ce56286671 68863
703441aa63c0ac1f39fe9e4a4cc8239a 47434
3fd023e7b2047e78c6742e2fc5b66fce 45350
a8b72ca65ba2440e8e4028a832ec2160 39524
...
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我想使用此查询中返回的MD5检索相应的客户端名称(FIRM),因此行可能如下所示:
879100cf8aa8b993a8c53f0137a3a176 126122 Burger King
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所以我提出了这个问题:
SELECT a.CLIENT_ID_MD5, COUNT(a.CLIENT_ID_MD5) TOTAL, c.FIRM
FROM dbo.amazonlogs a
INNER JOIN dbo.customers c
ON c.CLIENT_ID_MD5 = a.CLIENT_ID_MD5
GROUP BY a.CLIENT_ID_MD5, c.FIRM
ORDER BY COUNT(*) DESC;
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这返回类似于:
879100cf8aa8b993a8c53f0137a3a176 126122 Burger King
06c181de7f35ee039fec84579e82883d 88719 McDonalds
703441aa63c0ac1f39fe9e4a4cc8239a 47434 Wendy's
3fd023e7b2047e78c6742e2fc5b66fce 45350 Tim Horton's
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哪个有效,除非我需要为c.FIRM返回一个空值,如果给定的MD5没有相应的FIRM.例如:
879100cf8aa8b993a8c53f0137a3a176 126122 Burger King
06c181de7f35ee039fec84579e82883d 88719 McDonalds
69ffb6c6fd5f52de0d5535ce56286671 68863
703441aa63c0ac1f39fe9e4a4cc8239a 47434 Wendy's
3fd023e7b2047e78c6742e2fc5b66fce 45350 Tim Horton's
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即使没有相应的c.FIRM,我应该如何修改查询仍然返回一行?
evi*_*one 107
替换INNER JOIN为LEFT JOIN
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