Python - 单行与多行REGEX

Question

考虑以下文本模式,

#goals:进程报告时间戳,例如.2011-09-21 15:45:00和succ的前两个统计.统计线,例如: 1438 1439

input_text = '''
# Process_Name     ( 23387) Report at 2011-09-21 15:45:00.001    Type:  Periodic    #\n
some line 1\n
some line 2\n
some other lines\n
succ. statistics |     1438     1439  99 |   3782245    3797376  99 |\n
some lines\n
Process_Name     ( 23387) Report at 2011-09-21 15:50:00.001    Type:  Periodic    #\n
some line 1\n
some line 2\n
some other lines\n
succ. statistics |     1436     1440  99 |   3782459    3797523  99 |\n
repeat the pattern several hundred times...
'''

我在迭代迭代时得到它,

def parse_file(file_handler, patterns):

    results = []
    for line in file_handler:
        for key in patterns.iterkeys():
            result = re.match(patterns[key], line)
            if result:
                results.append( result )

return results

patterns = {
    'report_date_time': re.compile('^# Process_Name\s*\(\s*\d+\) Report at (.*)\.[0-9]   {3}\s+Type:\s*Periodic\s*#\s*.*$'),
    'serv_term_stats': re.compile('^succ. statistics \|\s+(\d+)\s+   (\d+)+\s+\d+\s+\|\s+\d+\s+\d+\s+\d+\s+\|\s*$'),
    }
results = parse_file(fh, patterns)

回国

[('2011-09-21 15:40:00',),
('1425', '1428'),
('2011-09-21 15:45:00',),
('1438', '1439')]

但有一个元组输出列表作为我的目标,

[('2011-09-21 15:40:00','1425', '1428'),
('2011-09-21 15:45:00', '1438', '1439')]

我尝试了几个具有初始模式和它们之间的惰性量词的组合,但无法弄清楚如何使用多线REGEX捕获模式

# .+?   Lazy quantifier "match as few characters as possible (all characters allowed) until reaching the next expression"
pattern = '# Process_Name\s*\(\s*\d+\) Report at (.*)\.[0-9]{3}\s+Type:\s*Periodic.*?succ. statistics) \|\s+(\d+)\s+(\d+)+\s+\d+\s+\|\s+\d+\s+\d+\s+\d+\s+\|\s'
regex = re.compile(pattern, flags=re.MULTILINE)

data = file_handler.read()    
for match in regex.finditer(data):
    results = match.groups()

我怎么能做到这一点？

Answer 1

使用re.DOTALLso .将匹配任何字符,包括换行符:

import re

data = '''
# Process_Name     ( 23387) Report at 2011-09-21 15:45:00.001    Type:  Periodic    #\n
some line 1\n
some line 2\n
some other lines\n
succ. statistics |     1438     1439  99 |   3782245    3797376  99 |\n
some lines\n
repeat the pattern several hundred times...
'''

pattern = r'(\d{4}-\d{2}-\d{2} \d{2}:\d{2}:\d{2}).*?succ. statistics\s+\|\s+(\d+)\s+(\d+)'
regex = re.compile(pattern, flags=re.MULTILINE|re.DOTALL)

for match in regex.finditer(data):
    results = match.groups()
    print(results)

    # ('2011-09-21', '1438', '1439')