在python中的迭代器/生成器中异常提升后继续

Question

Python中是否有任何方法可以在迭代器/生成器抛出异常后继续迭代？就像下面的代码一样,有没有办法跳过ZeroDivisionError并继续循环而gener()没有modyfying run()函数？

def gener():
    a = [1,2,3,4,0, 5, 6,7, 8, 0, 9]
    for i in a:
        yield 2/i

def run():
    for i in gener():
        print i

#---- run script ----#

try:
    run()
except ZeroDivisionError:
    print 'what magick should i put here?'

Answer 1

该逻辑位置try/except将是发生违规计算的地方:

def gener():
    a = [1,2,3,4,0, 5, 6,7, 8, 0, 9]
    for i in a:
        try:
            yield 2/i
        except ZeroDivisionError:
            pass