如何管理我的实体对象,以便将其删除?

Ala*_*ect 1 jpa jpa-2.0

这不起作用 - 我总是抛出IllegalArgumentException,并提出"尝试合并分离并再次尝试删除"的建议.

@PersistenceContext private EntityManager   em;
@Resource           private UserTransaction utx;
public void delete(EN entity) {
    if (entity == null) return;   // null-safe
    EN target = entity;
    try {
        if (!em.contains(entity)) {
            System.out.println("delete() entity not managed: " + entity);
            utx.begin();
            target = em.merge(entity);
            utx.commit();
            System.out.print("delete() this entity should now be managed: " + em.contains(target));
        }
        utx.begin();
        em.remove(target);
        utx.commit();
    } catch (RollbackException ex) {
        Logger.getLogger(this.getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (HeuristicMixedException ex) {
        Logger.getLogger(this.getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (HeuristicRollbackException ex) {
        Logger.getLogger(this.getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (SecurityException ex) {
        Logger.getLogger(this.getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (IllegalStateException ex) {
        Logger.getLogger(this.getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (NotSupportedException ex) {
        Logger.getLogger(this.getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (SystemException ex) {
        Logger.getLogger(this.getClass().getName()).log(Level.SEVERE, null, ex);
    }
}
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输出日志显示以下内容:

INFO: delete() entity not managed: com.database.SomeTable[ id=2 ]  
INFO: delete() this entity should now be managed: false
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换句话说,merge()不返回托管实体.谁能发现我做错了什么?

第二个问题:有没有办法在一个交易中而不是两个交易中执行此操作?

这是使用GlassFish 3.1中的EclipseLink.

Vin*_*lds 5

这段代码创建了两个事务:

if (!em.contains(entity)) {
    System.out.println("delete() entity not managed: " + entity);
    utx.begin();
    target = em.merge(entity);
    utx.commit();
    System.out.print("delete() this entity should now be managed: " + em.contains(target));
}
utx.begin();
em.remove(target);
utx.commit();
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虽然实体合并到持久性上下文中是正确的,但它仅适用于第一个事务,而不适用于两者.在第二个事务中,与事务关联的持久性上下文将再次找到作为参数传递的分离对象,如下所示:

em.remove(target);
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因为,以前utx.commit()会分开引用target.

要解决此问题,必须将实体合并到持久性上下文中,并在分离引用之前删除同一事务中的实体:

if (!em.contains(entity)) {
    System.out.println("delete() entity not managed: " + entity);
    utx.begin();
    target = em.merge(entity);
    em.remove(target);
    utx.commit();
    System.out.print("delete() this entity should now be deleted: " + (!em.contains(target)) );
}
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