如何在ListFragment中覆盖LongPress？

Question

我有一个ListFragment活动.

我想为onItemClickedLongPress创建一个方法,以便在用户执行此操作时.弹出一个菜单.我熟悉创建菜单.

所以,如果有人愿意,请给我进一步说明如何在ListFragment活动中设置覆盖longpress？

Answer 1

编辑:此示例显示如何显示系统菜单fx之外的其他内容.来自https://github.com/lorensiuswlt/NewQuickAction的 QuickAction

@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
    super.onViewCreated(view, savedInstanceState);
    //.......
    registerForContextMenu(getListView());
}

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    AdapterView.AdapterContextMenuInfo amenuInfo = (AdapterView.AdapterContextMenuInfo) menuInfo;
    Object item = getListAdapter().getItem(amenuInfo.position);
    //item could be Cursor/String/YourObject it depends on Adapter
    //show popup fx. QuickAction from https://github.com/lorensiuswlt/NewQuickAction
    QuickAction qa = new QuickAction(getActivity());
    qa.setAnimStyle(QuickAction.ANIM_AUTO);
    qa.show(amenuInfo.targetView);
}

编辑:这个ansewer不好 ...为什么我这样做这种奇怪的方法？因为Eclipse的智能感知不propmt"好" setOnLongClickListener的ListView(因为ListView至少有2种setOnLongClickListener方法......从一个View和第二从AdapterView类)......最简单的方法就是让你的ListFragment实现AdapterView.OnItemLongClickListener,然后onViewCreated添加代码getListView().setOnLongClickListener(this);

Answer 2

通过"长按",我认为你指的是上下文菜单.对于a ListFragment,您应该做的就是注册上下文菜单:

@Override
public void onActivityCreated(Bundle icicle) {    
    registerForContextMenu(getListView());
}

一旦你这样做,ListFragment应该打电话onCreateContextMenu(),onContextItemSelected()当它检测到长按.