如果我从方法中得到“None”，是否有提前返回的方法？

Question

None如果我从方法中获取 a ，是否有提前返回的方法？例子：

pub async fn found_player(id: &str) -> Result<Option<Player>> {
    let player = repo // player here is Option<Player>
        .player_by_id(id)
        .await?; // I would like to use here a magic method to return here immediately if is None with `Ok(None)`
  
    if player.is_none() {
        return Ok(None);
    }

    // Do some stuff here but WITHOUT using player.unwrap(). I would like to have it already unwrapped since is not None

    Ok(Some(player))
}

我尝试过类似的事情Ok_or()，但我认为它们现在就是我所需要的。我能怎么做？

我不想使用matchorif else因为我需要尽可能少一些冗长。

Answer 1

可用的最短语法类似于：

let Some(player) = repo.player_by_id(id).await? else {
    return Ok(None);
};
// player is Player here

在 Rust 1.65 之前，必须使用 or 来match拼写if let：

let player = match repo.player_by_id(id).await? {
    Some(player) => player,
    None => return Ok(None),
};
// player is Player here