use*_*400 3 c# wpf xaml listview
我开始玩wpf listview控件.我创建了一个"添加"按钮和一个"编辑"按钮."添加"按钮按预期工作 - 每当我向列表添加新项目时,它都会显示出来.我的问题是"编辑"按钮 - 通知listView控件项目被更改的正确方法是什么?(它在附加的代码中工作,我只是想知道是否有更好的方法)
这是我的代码:
XAML:
<Window x:Class="WpfApplication5.MainWindow" Name="This"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525"
>
<Grid>
<ListView Name="Mylist"
ItemsSource= "{Binding ElementName=This, Path=People}"
SelectionMode="Single"
>
<ListView.View>
<GridView AllowsColumnReorder="false">
<GridViewColumn
Header="Name"
Width="Auto"
DisplayMemberBinding="{Binding Path=Name}" />
<GridViewColumn
Header="Id"
Width="Auto"
DisplayMemberBinding="{Binding Path=Id}" />
</GridView>
</ListView.View>
</ListView>
<StackPanel Orientation="Horizontal" Height="45" Margin="190,133,197,133">
<Button
Content="Add"
Click="AddButton_Click"
/>
<Button
Content="Edit"
Click="EditButton_Click"
/>
</StackPanel>
</Grid>
</Window>
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代码背后:
namespace WpfApplication5
{
public class PersonalDetails
{
public string Name {get; set;}
public string Id {get; set;}
}
public partial class MainWindow : Window
{
private ObservableCollection<PersonalDetails> people = new ObservableCollection<PersonalDetails>();
public ObservableCollection<PersonalDetails> People
{
get { return this.people; }
}
public MainWindow()
{
PersonalDetails p1 = new PersonalDetails();
p1.Name = "Jeff";
p1.Id = "111";
people.Add(p1);
InitializeComponent();
}
private void AddButton_Click(object sender, System.Windows.RoutedEventArgs e)
{
PersonalDetails p2 = new PersonalDetails();
p2.Name = "Tom";
p2.Id = "222";
people.Add(p2);
}
private void EditButton_Click(object sender, System.Windows.RoutedEventArgs e)
{
PersonalDetails pItem = (PersonalDetails)Mylist.SelectedItem;
if (pItem == null)
{
return;
}
pItem.Name = "Dan";
Mylist.Items.Refresh();
}
}
}
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谢谢,李
您的PersonalDetails类应实现INotifyPropertyChanged接口.
然后,当Name属性更改并引发PropertyChanged事件时,WPF绑定基础结构将通过刷新演示文稿进行响应.
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