log4perl如何同时写入STDERR和文件？

Question

我试图设置两个appender,但似乎只写STDERR:

my $header = "######$scriptname $version";
use Log::Log4perl qw(:easy);
Log::Log4perl->easy_init($DEBUG);
my $logger = get_logger();
my $layout = Log::Log4perl::Layout::PatternLayout->new(
"%d %p> %F{1}:%L %M - %m%n");
my $appender = Log::Log4perl::Appender->new(
        "Log::Dispatch::File",
        filename=>$scriptname.".log",
        mode => "append"
);
$appender->layout($layout);
my $stderr = Log::Log4perl::Appender::Screen->new(
        stderr =>0,
        );

$stderr->layout($layout);
$logger->info($header);

Answer 1

easy_init与自定义appender 混合不是一个好主意.您可以通过向记录器添加appender来解决此问题$logger->add_appender($appender).但这会导致重复的消息,因为你已经设置了appender easy_init.

我建议你改用配置.您可以在代码中嵌入配置:

use strict; use warnings;

use Log::Log4perl;

Log::Log4perl->init(\<<CONFIG);
log4perl.rootLogger = DEBUG, screen, file

log4perl.appender.screen = Log::Log4perl::Appender::Screen
log4perl.appender.screen.stderr = 0
log4perl.appender.screen.layout = PatternLayout
log4perl.appender.screen.layout.ConversionPattern = %d %p> %F{1}:%L %M - %m%n

log4perl.appender.file = Log::Log4perl::Appender::File
log4perl.appender.file.filename = 1.log
log4perl.appender.file.mode = append
log4perl.appender.file.layout = PatternLayout
log4perl.appender.file.layout.ConversionPattern = %d %p> %F{1}:%L %M - %m%n
CONFIG

my $logger = Log::Log4perl->get_logger();
$logger->info("my message");