Jos*_*hlo 4 maui .net-maui maui-windows
我试图隐藏桌面上图像中显示的后退按钮,但无论我尝试什么,它都会继续显示。
我努力了
<Shell.BackButtonBehavior>
<BackButtonBehavior IsVisible="False" IsEnabled="False" />
</Shell.BackButtonBehavior>
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我已经尝试遵循这篇文章为什么后退按钮隐藏在毛伊岛?
我的导航是这样完成的await Shell.Current.GoToAsync(new ShellNavigationState(location), false);
我错过了什么吗?
Cod*_*ian 11
This technique (the code in your question), added within the <ContentPage ... > declaration at the top of the xaml:
<Shell.BackButtonBehavior>
<BackButtonBehavior IsVisible="False" IsEnabled="False" />
</Shell.BackButtonBehavior>
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seems to work when using the Shell to activate pages in C# codebehind (often in the BindingSource e.g., viewmodel):
await Shell.Current.GoToAsync($"{nameof(MyContentPage)}");
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Adding this within the <ContentPage ...> declaration at the top of the xaml:
NavigationPage.HasBackButton="false"
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seems to be applicable when using the push/pop within a NavigationPage:
await Navigation.PushAsync(new DetailsPage());
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I don't use the Navigation.PushAsync. My app requires very specific navigation based on current data state, so a stack doesn't work for me. I have verified setting the Shell.BackButtonBehavior (in the very code you provided) works in my case because I am activating pages via
await Shell.Current.GoToAsync
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