Removing everything except numbers inside braces and some characters

Question

Want to remove everything except # NewLine, complete bracket set and numbers inside braces.
Sample input:

# (1296) {20} [529] [1496] [411]
# (MONDAY ) (1296)
# (646) {20} (BEACH 7) [20 Mtrs] { 03 Foot }
# {19} [455] [721] (1296) (SUNDAY ) [2741] (MONDAY (WEDNESDAY {20}
# {19} (1296)

Code which does not work:

$re = '/(?:\[[^][]*]|\([^()]*\)|{[^{}]*})(*SKIP)(*F)|[^][(){}@#]+/m';
$result = preg_replace($re, '', $input);

Incorrect output:

#(1296){20}[529][1496][411]
#(1296) 
#(646){20}(BEACH 7)[20 Mtrs]{ 03 Foot }
#{19}[455][721](1296)[2741](({20}
#{19}(1296)

Desired output:

#(1296) {20} [529] [1496] [411]
#(1296)
#(646) {20}
#{19} [455] [721] (1296) [2741] {20}
#{19} (1296)

Answer 1

您可以在括号之间匹配至少 1 位数字，然后跳过该匹配。

然后匹配除换行符或#替换为空字符串之外的任何字符。

(?:\[\h*\d[\h\d]*]|\(\h*\d[\h\d]*\)|{\h*\d[\h\d]*})\h*(*SKIP)(*F)|[^#\n]

解释

• (?:非捕获组
  • \[\h*\d[\h\d]*]匹配方括号之间至少 1 个数字，其中\h匹配水平空白字符（无换行符）
  • |或者
  • \(\h*\d[\h\d]*\)括号内为 1 位数字
  • |或者
  • {\h*\d[\h\d]*}大括号之间有 1 位数字
• )\h*关闭非捕获组并匹配 1+ 个空格
• (*SKIP)(*F)跳过并失败匹配（使其在输出中保持不变）
• |或者
• [^#\n]#匹配除或 换行符之外的任何字符

正则表达式演示