在非常简单的示例中使用EasyMock.expect()时编译错误？

Question

我正在尝试使用EasyMock的一个非常简单的例子,但是我根本无法构建它.我有以下测试用例:

@Test
public void testSomething()
{
    SomeInterface mock = EasyMock.createMock(SomeInterface.class);
    SomeBase expected = new DerivesFromSomeBase();

    EasyMock.expect(mock.send(expected));
}

但是我EasyMock.expect(...在行中收到以下错误:

The method expect(T) in the type EasyMock is not applicable for the arguments (void)

有人能指出我正确的方向吗？我完全迷失了.

Answer 1

如果要测试void方法,请在模拟上调用要测试的方法.然后调用该expectLastCall()方法.

这是一个例子:

@Test
public void testSomething()
{
    SomeInterface mock = EasyMock.createMock(SomeInterface.class);
    SomeBase expected = new DerivesFromSomeBase();

    mock.send(expected);

    EasyMock.expectLastCall().andAnswer(new IAnswer<Object>() {
        public Object answer() {
            // do additional assertions here
            SomeBase arg1 = (SomeBase) EasyMock.getCurrentArguments()[0];

            // return null because of void
            return null;
        }
    });
}

Answer 2

由于send()方法返回void,因此只需使用期望值调用mock方法并重放:

SomeInterface mock = EasyMock.createMock(SomeInterface.class);
SomeBase expected = new DerivesFromSomeBase(); 
mock.send(expected);
replay(mock);