我正在尝试绘制一些我从外部来源提取的成绩.日期格式如下所示:
2011-08-23T17:07:05
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所以我解析它strptime(date, "%FT%X")并得到一个POSIXlt.我最终得到了一个完整的数据框,如下所示:
date subject grade
1 2011-08-23 17:07:05 AP Biology 95.83
2 2011-08-24 17:07:03 AP Biology 95.83
3 2011-08-25 17:08:27 AP Biology 95.83
4 2011-08-17 17:05:54 US History 157.14
5 2011-08-18 17:05:24 US History 157.14
6 2011-08-19 17:05:35 US History 157.14
7 2011-08-22 17:06:25 US History 157.14
8 2011-08-23 17:07:05 US History 157.14
9 2011-08-24 17:07:03 US History 157.14
10 2011-08-25 17:08:27 US History 157.14
11 2011-08-19 17:05:35 Yearbook 0.00
12 2011-08-22 17:06:25 Yearbook 0.00
13 2011-08-23 17:07:05 Yearbook 100.00
14 2011-08-24 17:07:03 Yearbook 100.00
15 2011-08-25 17:08:27 Yearbook 100.00
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具有以下结构:
'data.frame': 15 obs. of 3 variables:
$ date : POSIXlt, format: "2011-08-23 17:07:05" "2011-08-24 17:07:03" ...
$ subject: Factor w/ 3 levels "AP Biology","US History",..: 1 1 1 2 2 2 2 ...
$ grade : num 95.8 95.8 95.8 157.1 157.1 ...
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当我尝试绘制这些数据时:
> ggplot(data=grades, aes(date, grade, factor=subject)) + geom_line()
Error in if (length(range) == 1 || diff(range) == 0) { :
missing value where TRUE/FALSE needed
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我不知道我在这里做错了什么.我通过这样做将其缩小到日期处理:
ggplot(data=grades,
aes(seq(length(grades[,1])),
grade, color=subject)) + geom_line()
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...但是如何正确处理日期?
rcs*_*rcs 12
POSIXctggplot2 只支持类的次数.Class POSIXct表示自1970年初(UTC时区)以来的(带符号)秒数作为数字向量.类POSIXlt是表示九个元素(向量的命名列表sec,min,hour等等).
您可以使用以下内容:
grades$date <- as.POSIXct(grades$date)
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