我正在尝试使用DeflaterOutputStream将JSON字符串往返一个字节数组,但下面的代码是抛出的java.io.EOFException: Unexpected end of ZLIB input stream.
将字符串替换为"Hello world"时,或者从下面的字符串中删除一些字符时,它可以正常工作.
有任何想法吗?
public static void main(String[] args) throws IOException {
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
DeflaterOutputStream deflate = new DeflaterOutputStream(bytes, new Deflater(Deflater.BEST_COMPRESSION, true));
OutputStreamWriter writer = new OutputStreamWriter(deflate);
writer.write("[1,null,null,\"a\",null,null,null,null,[1,null,null,null,null,null,null,null,null,null,null,null,null,0.0,0.0,null,null]");
writer.flush();
writer.close();
InflaterInputStream inflaterIn = new InflaterInputStream(new ByteArrayInputStream(bytes.toByteArray()), new Inflater(true));
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inflaterIn));
System.out.println(bufferedReader.readLine());
}
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Java版本(OSX):
java version "1.6.0_26"
Java(TM) SE Runtime Environment (build 1.6.0_26-b03-383-11A511)
Java HotSpot(TM) 64-Bit Server VM (build 20.1-b02-383, mixed mode)
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我相信这是与你传递"真"在这两个"无包装"选项做Deflater和Inflater.设置这两个以false解决问题 - 虽然我建议在两个地方设置字符串编码(例如UTF-8),而不是使用系统默认编码.
"nowrap"的文档相当含糊,但它们指出:
注意:使用'nowrap'选项时,还需要提供额外的"虚拟"字节作为输入.这是ZLIB本机库所必需的,以支持某些优化.
大概这个虚拟输入字节丢失了,虽然它没有解释它应该去哪里......
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